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1. CARTESIAN COMPLEX NUMBERS - Weebly

UNIVERSITI KUALA LUMPUR COMPLEX number E2 1. CARTESIAN COMPLEX NUMBERS INTRODUCTION Try to solve this quadratic equation : 0522=++xx By using quadratic formula : the discriminant , 16)5)(1(4)2(422 = = = acb the solution : )1(216)2( =x but it is not possible to evaluate 1 however if an operator j is defined as then the solution may be expressed as : 12 =j 21242)1(216)2(jjx = = = 21j+ and are known as COMPLEX NUMBERS .

COMPLEX NUMBER – E2 1. CARTESIAN COMPLEX NUMBERS 1.1 INTRODUCTION Try to solve this quadratic equation : x2 +2x+5 =0 By using quadratic formula : the discriminant , ∆=b2 −4ac =(2)2 −4(1)(5) =−16 the solution : 2(1) −(2)± −16 x = but it is not possible to evaluate −1 however if an operator j is defined as

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  Number, Complex, Cartesian, Cartesian complex numbers

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