1 Notes on Little’s Law (l w
Dividing the rst piece by tand letting t!1yields w=(1 + ) by the same argument used on the upper bound in (7). The second piece is a constant hence when divided by t, tends to 0. Thus we conclude that for any >0, lim t!1 1 t X fj:td j tg W j w=(1 + ): Since >0 was chosen arbitrary, we conclude that (19) holds.
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