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建築構造学講義(2) - archi.hiro.kindai.ac.jp

1 2 3 MEI = FMFL=L4 etc. 5 6 7 F4 FLM=LF bh()maxmaxmaxmaxmax24326 NMNFNAbhFLLMZhbh == === maxNF=max4 FLM= 8 9 10 11 12 13 14 15 16 17 16 18 19 20 21 22 2006 23 24 25 26 27 28 29 30 31

3 構造力学なら簡単に説明できる 断面 m =eiφ 断面2次モーメントが大きくなる 曲げに対する抵抗力が大きくなる m =fl f l

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