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2. Higher-order Linear ODE’s

2. Higher-order Linear ODE s2A. Second- order Linear ODE s: General the right below is an abbreviated form of the ODE on the left:(*)y +p(x)y +q(x)y=r(x)Ly=r(x) ;whereLis thedifferential operator:L=D2+p(x)D+q(x).a) Ifu1andu2are any two twice-differentiable functions, andcis a constant, thenL(u1+u2) =L(u1) +L(u2)andL(c u) =c L(u).Operators which have these two properties are calledlinear. Verify thatLis Linear , ,that the two equations are ) Show that ifypis a solution to (*), then all other solutions to (*) can be written inthe formy=yc+yp,whereycis a solution to theassociated homogeneous equationLy= ) By eliminating the constants, find a second- order Linear homogeneous ODE whosegeneral solution isy=c1ex+ ) Verify for this ODE that the IVP consisting of the ODE together with the initialconditionsy(x0) =y0,y (x0) =y 0y0, y 0constantsis always ) By eliminating the constants, find a second- order Linear homog

2E-8.* By using Eulers formula and the binomial theorem, express cos3θ and sin3θ in terms of cosθ and sinθ. 2E-9. Express in the form a+bi the six sixth roots of 1. 2E-10. Solve the equation x4 +16 = 0. 2E-11.* Solve the equation x4 + 2x2 + 4 = 0, expressing the four roots in both the polar form and the Cartesian form a+bi. 2E-12.*

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  Higher, Linear, Order, Euler, Higher order linear ode s

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