7.2. R = (A, B, C, D, E). We decompose it into R = (A, B ...
2. Decomposition of R 1 by E → B. R 11 = (A, E), R 12 = (B, E). (A, E), (B, E) and (A, C, D) form a decomposition into BCNF. 2) 1. A → CD R 1 = (A, C, D). 2. B → CE R 2 = (B, C, E). 3. E → B , but E, B are in R 2. 4. A candidate key is AB (or AE). It is neither in R 1 nor in R 2. Hence, we add R 3 = (A, B). The decomposition we got is ...
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