Transcription of Algebra 1 - Solving Equations by Cross Multiplication
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D L2A0y143z OKMuqteal hSjorf7tDwxairye5 h 5 AxlAll trfi7gghNtDs1 r nMeaSdBeK 7wfiDtThO cILnIf9i1n8iytmeQ by Kuta Software LLCA lgebra 1 Name_____ Period____Date_____ Y 62q0v1C30 PKkuHt9au 3 SbobfBtXwoanr0eW w aA9lHlQ ursiVgDhqtjsj Equations by Cross MultiplicationSolve each ) n5 = 672) 48 = v63) 97 = k24) 210 = 10 x5) 75 = 6 n6) 49 = 9 m7) b9 = 1038) 36 = 5 r9) 54 = p510) x10 = 96-1- N 92004173o CKaumtBaw xSSovfkt0wtagroe7 J 4A6lXlQ LrviWg4hEtMsn t pMFaYdLeH bwgiFtphm iIwnxflipnbiatReg by Kuta Software LLC11) n + 77 = 4912) 69 = 2 x 513) 810 = a + 1314) 43 = p + 6815) 8 m 4 = 6216) 37 = 5 n 817) 83 = 7 k 218) 710 = x + 3419) 310 = x + 2820) 78 = 3 x 6-2- K F2S0U1S3g SKzuJtiav jSGoqfqtowGa2r9er m XAEl3ld VrRiWg8hatGsI V LMqazdQeK dw0iutphw pIjnnfNixnZiltweJ by Kuta Software LLC21) n + 54 = n622) n + 44 n = 6423) 10 x = 6 x 924) 6 v = 8 v + 425) a a 10 = 6926) 10 a = 8 a + 1027) r r + 5 = 7528) x5 = x + 4729) x + 10 x = 51030) b2 = b 19-3- M d2W0n1W3B AKbunt0aU OSIoSfDtfwwawrxeE f mAcltlm LrnikgRh6t6sq 7 zMtaUdmey 9wJiztdhq KI3nTfpiNn0iWtx
Solving Equations by Cross Multiplication Solve each proportion. 1) n 5 = 6 7 2) 4 8 = v 6 3) 9 7 = k 2 4) 2 10 = 10 x 5) 7 5 = 6 n 6) 4 9 = 9 m 7) b 9 = 10 3 8) 3 6 = 5 r 9) 5 4 = p 5 10) x 10 = 9 6-1-©N 92041 73o CKaumtBaw xSSovf kt0w ta gr oe7 FL vL mCX.p J 4A6lXlQ Lr viWg4hEt Msn dr 2eQs1e sr 7vvesdX.6 t pMFaYdLeH bwgiFtph m iI wnxflipn ...
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