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Chap 3 : Two Random Variables

Chap 3: Two Random Variables where X i is the indicator RV, given as P[X i =1]=P{ith man selects his own hat} =1/N So E[X i]=1P[X i =1]+0P[X i =0]=1/N Therefore, E[X]=E[X1]+E[X2]+···+E[X N]=1. No matter how many people are at the party, on the average, exactly one of the men will select his own hat. 16

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