Chapter 1 Solutions to Review Problems
1 −3 2 5 2 6 −9 15 Now, add to the second row −6 times the first row to obtain 1 −3 2 5 2 0 0 0 Hence, x 2 = s is a free variable. Solving for x 1 we find x 1 = 5+3t 2.The system is consistent. (c) Note that according to the given equation 1 = 3 which is impossible. So the given system is …
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