Transcription of CHAPTER 14 | Chemical Equilibrium: Equal but …
{{id}} {{{paragraph}}}
Example: barber
CHAPTER 14 | Chemical Equilibrium: Equal but …
112 CHAPTER 14 | Chemical equilibrium : Equal but opposite Reaction Rates Collect and Organize For two reversible reactions , we are given the reaction profiles (Figure ). The profile for the conversion of A to B shows that reactant A has a lower free energy than product B. The profile for the conversion of C to D shows that C has a higher free energy than D. From the profiles, we are to determine which reaction has the larger kf, the smaller kr, and the larger value of Kc. Analyze The magnitude of the rate constant is inversely related to the magnitude of the activation energy, Ea. The reaction with the larger kf, smaller kr, and the larger Kc is that reaction with the lowest Ea for the forward reaction and where kf > kr. Solve The reaction C D has the larger kf, the smaller kr, and the larger Kc (because it has the lowest activation energy for the forward direction). Think about It Remember that a large k (rate constant) means that the reaction is fast and therefore the reaction has a low activation energy.
112 CHAPTER 14 | Chemical Equilibrium: Equal but Opposite Reaction Rates 14.1. Collect and Organize For two reversible reactions, we …
Loading..
Tags:
Information
Domain:
Source:
Link to this page:
Please notify us if you found a problem with this document:
Related search queries
To Chapter 13. Chemical Equilibrium, Equilibrium, Chapter 14 Chemical Equilibrium, Chapter 14, Chapter 14 Chemical Equilibrium Chemical equilibrium, Chapter, CHAPTER 14 (MOORE) CHEMICAL EQUILIBRIUM, Chemical Equilibrium, Chemical, Chapter 14. Chemical Equilibrium, CHAPTER 14 Chemical Equilibrium-A Dynamic, Chemical Equilibrium-A Dynamic Equilibrium, Chemical Equilibrium 1– Chapter 14, The Process of Chemical Reactions