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Chemistry 192 Problem Set 6 Spring, 2018 Solutions

Chemistry 192 Problem Set 6 spring , 2018 Solutions1. The solubility product of Al(OH)3is 10 15. Calculate the concentrations ofaluminum ions, hydroxide ions and hydronium ions in a saturated aqueous solution ofaluminum :Al(OH)3(s) Al3+(aq)+ 3OH (aq)Ksp= [Al3+][OH ]3= 10 15[Al3+][OH ]initial0 M0 Mchanges3sequilibriumsM3sM27s4= 10 15s= [Al3+] = 10 5M[OH ] = 3s= 10 4M[H3O+] = 10 10 4= 10 112. The solubility product of Ag2S is 10 49. Calculate the molar solubility of silversulfide in :Ag2S(s) 2Ag+(aq)+ S2 (aq)[Ag+][S2 ]initial0 M0 Mchange2ssequilibrium2sMsM1(2s)2s= 4s3= 10 49s= molar solubility = 10 17M3. The solubility of Ag3 AsO4in water is 10 4g mL 1. Calculate the solubilityproduct of silver :Ag3 AsO4(s) 3Ag+(aq)+ AsO3 4(aq)moles dissolved of silver arsenate = 10 4g463 g mol 1= 10 6mol[AsO3 4] = 10 L= 10 3M[Ag+] = 3[AsO3 4] = 10 3 MKsp= ( 10 3)3( 10 3) = 10 104.

having formation equilibrium constant K f = 4:1 108. Zinc sul de (ZnS) is only spar-ingly soluble in water with solubility product constant K sp = 2:0 10 25. Calculate the molar solubility of zinc sul de in a 0.10 M aqueous ammonia solution. Approximations work for this system. Answer: ZnS (s) + 4NH 3(aq) *) Zn(NH 3) 2+ 4(aq) + S 2 (aq) K = K ...

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  Product, Solutions, Constant, Chemistry, 2018, Problem, Solubility, Spring, Solubility product constant, 2018 solutions, Chemistry 192 problem set 6 spring

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