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Circular Motion Problems ANSWERS

Ftension Fgravity= N Circular Motion Problems ANSWERS 1. An g cork is swung in a horizontal circle with a radius of 35 cm. It makes 30 revolutions in 12 seconds. What is the tension in the string? (Assume the string is nearly horizontal) T=time/revolutions= s Period is the time per revolution F=ma Write down N2L Ftension = mv2/r Tension provides net force, acceleration is centripetal Ftension=m(4 2r/T2) Speed equals circumference divided by period Ftension= N Substitute values and calculate 2. A 15 g stopper is swung in a horizontal circle with a radius of meters. The tension in the string is Newtons. Find the speed of the stopper and determine how long it takes to complete 30 revolutions.

Dec 11, 2012 · Kepler’s third law of planetary motion. Phobos: r=9400 km T=7.66 hours Deimos: r=23,500 km T=30.4 hours (T2/r3) = 7.06x10-11 hr2/km3 (phobos) (T2/r3) = 7.12x10-11 hr2/km3 (deimos) Since only 2 significant digits were given for the orbital radius of Phobos we can conclude that the data ARE consistent with Kepler’s Third Law 12.

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