Transcription of EE101: RLC Circuits (with DC sources)
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EE101: RLC Circuits (with DC sources) M. B. of Electrical EngineeringIndian Institute of Technology BombayM. B. Patil, IIT BombaySeriesRLCcircuitRLiCVRVCVLV0 KVL:VR+VL+VC=V0 i R+Ldidt+1 CZi dt=V0 Differentiating w. r. , we get,Rdidt+Ld2idt2+1Ci= ,d2idt2+RLdidt+1 LCi= 0 ,a second-order ODE with constant B. Patil, IIT BombaySeriesRLCcircuitRLiCVRVCVLV0 KVL:VR+VL+VC=V0 i R+Ldidt+1 CZi dt=V0 Differentiating w. r. , we get,Rdidt+Ld2idt2+1Ci= ,d2idt2+RLdidt+1 LCi= 0 ,a second-order ODE with constant B. Patil, IIT BombaySeriesRLCcircuitRLiCVRVCVLV0 KVL:VR+VL+VC=V0 i R+Ldidt+1 CZi dt=V0 Differentiating w. r. , we get,Rdidt+Ld2idt2+1Ci= ,d2idt2+RLdidt+1 LCi= 0 ,a second-order ODE with constant B.
* A parallel RLC circuit driven by a constant voltage source is trivial to analyze. Since the voltage across each element is known, the current can be found in a straightforward manner. i R = V=R; i C = C dV dt; i L = 1 L Z V dt : * The above equations hold even if …
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