Transcription of EXAMPLE 1 - ETU
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EXAMPLE 1 - ETU
Fig. 1 4bFig. 1 the resultant internal loadings acting on the cross sectionat Cof the beam shown in Fig. 1 N/m540 N2 m4 mVCMCNC(b)BC(a)ABC3 m6 m270 N/mFig. 1 4 SolutionSupport problem can be solved in the most directmanner by considering segment CBof the beam, since then thesupport reactions at Ado not have to be an imaginary section perpendicular to thelongitudinal axis of the beam yields the free-body diagram of segmentCBshown in Fig. 1 4b. It is important to keep the distributed loadingexactly where it is on the segment until afterthe section is made. Onlythen should this loading be replaced by a single resultant force. Noticethat the intensity of the distributed loading at Cis found by proportion, , from 4a,Themagnitude of the resultant of the distributed load is equal to the areaunder the loading curve (triangle) and acts throughthe centroid of ,which acts from Cas shown in Fig.
Fig. 1–6a EXAMPLE 1.3 The hoist in Fig. 1–6a consists of the beam AB and attached pulleys, the cable, and the motor. Determine the resultant internal loadings acting on the cross section at C if the motor is lifting the 2000 N ( 200 kg) load W with constant velocity. Neglect the weight of the
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