Integrating an Absolute Value - University of Alaska system
jx3 5x2 + 6xjdx = applying the de nition of absolute value Z 2 0 x3 5x2 + 6x dx+ Z 3 2 (x3 5x2 + 6x) dx+ Z 4 3 x3 5x2 + 6x dx = using anti-derivative 1 4 x4 5 3 x3 + 3x2 2 0 + 1 4 x4 + 5 3 x3 3x2 3 2 + 1 4 x4 5 3 x3 + 3x2 4 3 = 8 3 + 5 12 + 37 12 = 74 12: Created Date:
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