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Integration by Partial Fractions

Joe FosterIntegration by Partial FractionsSummary: Method of Partial Fractions whenf(x)g(x)is proper (degf(x)<degg(x))1. Letx rbe a linear factor ofg(x). Suppose that (x r)mis the highest power ofx rthat dividesg(x). Then, tothis factor, assign the sum of thempartial Fractions :A1(x r)+A2(x r)2+A3(x r)3+ +Am(x r) this for each distinct linear factor ofg(x).2. Letx2+px+qbe an irreducible quadratic factor ofg(x) so thatx2+px+qhas no real roots. Suppose that(x2+px+q)nis the highest power of this factor that dividesg(x). Then, to this factor, assign the sum of thenpartial Fractions :B1x+C1(x2+px+q)+B2x+C2(x2+px+q )2+B3x+C3(x2+px+q)3+ +Bnx+Cn(x2+px+q) this for each distinct quadratic factor ofg(x).

There is no indicator of what the numerators should be, so there is work to be done to find them. If we let the numerators be variables, we can use algebra to solve. That is, we want to find constants A and B that make the equation below true for all x 6= −5,−2. x +14 (x +5)(x +2) = A x +5 + B x +2. We solve for A and B by cross ...

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