実験計画法 - lab.sdm.keio.ac.jp

11/29. 8.. A B . A B . B1 B2 B3 B4 xi . A1 76 77 77 74 78 79 78 75. A2 73 75 75 72 72 75 73 74. x j x = n: a:A b:B r: . B A A . B . B1. A B . A B A B B2. (1) A1 A2. xijk= ij+ ijk= +( ) +( .j- )+( ij- .j+ )+ ijk= + i+ j+( )ij+ ijk . a ij i A i =0. i =1..j b j B j =0. j =1 i. a b . ( )ij A B ( ) ij ( ) ij = 0. = 0, i =1 j =1. ijk ijk N(0, 2) . (2) . x ijk x = ( x ij x ) + ( x ijk xij ). AB . = ( xi x ) + ( x j x ) + ( xij x i x j + x ) + ( xijk xij ). A B A B . - 25 - a b r S T = ( x ijk x ) 2. i =1 j =1 k =1. a b r AB S AB = ( xij x ) 2. i =1 j =1 k =1. a b r a A S A = ( x i x ) 2 = rb ( x i x ) 2. i =1 j =1 k =1 i =1. a b r b B S B = ( x j x ) 2 = ra ( x j x ) 2. i =1 j =1 k =1 j =1. a b r a b A B S A B = ( x ij x i x j + x ) 2 = r ( x ij x i x j + x ) 2.

11/29 . 8. 二元配置 （学習内容） ・交互作用について理解する ・二元配置の分散分析法の手順を学ぶ . 8.1二元配置の考え方

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