Lect10 - Columns Interaction Diagrams

` =f ~ =. a ~ ~ . rkfsbopfqv=lc=tfp`lkpfk=pqlrq `liibdb=lc=p`fbk`bI=qb`eklildvI=bkdfkbbo fkdI=^ka=j^qebj^qf`p ib`qrob=u a K=g~ =bK=` ~ ~ ~ . ` = =. ` ~ =j~ ~ . Let's try to visualize the effect of strength and the geometry that would correspond to a design for a specific load. Let's take two very prominent materials: Steel: E=29000000psi Concrete: E=3600000psi It is obvious that in order to compensate the strength difference, we will address the geometric form, the cross sectional area. So a Steel column can be way more slender than a concrete column, just to bear the load. t ~ =f =q =b =l =. ` =p \. Imagine the effect of purely axial load applied in this element. What do you think will happen? Even if there is no shear or moment applied, do you believe that it will crush from the axial load?

bñ~ãéäÉ=ÅçåíK Ec 57000 f'c Ec 4030.509ksi= ksi 1000 := Determining the modulus of elasticity of Concrete: Cm 0.6 0.4 Cm 1= M1 M2 := + Determining the Cm (factor relating the actual moment diagram of a slender column to an equivalent uniform

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  Interactions, Diagrams, Columns, Lect10 columns interaction diagrams, Lect10, Slender

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