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Lecture 2: Divide and Conquer - MIT OpenCourseWare

Lecture 2 Divide and Conquer Spring 2015. Lecture 2: Divide and Conquer Paradigm Convex Hull Median nding Paradigm Given a problem of size n Divide it into subproblems of size nb , a 1, b > 1. Solve each subproblem recursively. Combine solutions of subproblems to get overall solution. n T (n) = aT ( ) + [work for merge]. b Convex Hull Given n points in plane S = {(xi , yi )|i = 1, 2, .. , n}. assume no two have same x coordinate, no two have same y coordinate, and no three in a line for convenience. Convex Hull ( CH(S) ): smallest polygon containing all points in S. q v r p u t s CH(S) represented by the sequence of points on the boundary in order clockwise as doubly linked list.

Lecture 2 Divide and Conquer Spring 2015. Lecture 2: Divide and Conquer • Paradigm • Convex Hull • Median finding. Paradigm. Given a problem of size. n. divide it into subproblems of size. …

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Transcription of Lecture 2: Divide and Conquer - MIT OpenCourseWare

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