Transcription of Lecture 5 - UIUC
{{id}} {{{paragraph}}}
Example: bachelor of science
Lecture 5 - UIUC
Lecture 5, p 1 =2 = c0II0 Sum2I00 = c/3yyLecture 5:Applications of Interference and DiffractionLecture 5, p 2 TodayCircular Diffraction Angular resolution (Rayleigh s criterion) Minimum spot sizeInterferometers Michelson ApplicationsLecture 5, p 3 The size of the spot is determined by the diameter, D, of the aperture, and wavelength, , of the incident by a circular aperture is similar to single)slit diffraction. But note the difference:Image plane00II0 o DImage planePoint objecta Circular apertureThe Airy disk .The central lobe contains 84% of limited OpticsDiffraction has important implications for optical instrumentsEven for perfectly designed optics the image of a point source will be a little blurry ) the circular aperture produces diffraction.
Optical Interferometers Interference arises whenever there are two (or more) ways for something to happen, e.g., two slits for the light to get from the source to the screen. I = 4I1cos 2(φ/2), with φ= 2 πδ/λ , and path-length difference δ An interferometer is a …
Loading..
Tags:
Information
Domain:
Source:
Link to this page:
Please notify us if you found a problem with this document: