Transcription of March 6 Homework Solutions Math 151, Winter 2012 …
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March 6 Homework Solutions math 151, Winter 2012 . Chapter 6 Problems (pages 287-291). Problem 31. According to the National Center for Health Statistics, percent of males and percent of females never eat breakfast. Suppose that random samples of 200 men and 200 women are chosen. Approximate the probability that (a) at least 110 of these 400 people never eat breakfast. Let M denote the number of men that never eat breakfast and W denote the number of women that never eat breakfast. Note that M is a binomial random variable with p = .252 and n = 200, and W is a binomial random variable with p = .236 and n = 200. We compute E[M ] = 200(.252) = , Var(M ) = 200(.252)(1 .252) , E[W ] = 200(.236) = , Var(M ) = 200(.236)(1 .236) Thus we may approximate M by a normal random variable with = and 2 and we may approximate W by a normal random variable with = and 2 We want to compute P {110 M + W }.
March 6 Homework Solutions Math 151, Winter 2012 Chapter 6 Problems (pages 287-291) Problem 31 According to the U.S. National Center for Health Statistics, 25.2 percent of males and 23.6 percent of females never eat breakfast. Suppose that random samples of 200 men and 200 women are chosen. Approximate the probability that
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