Math 115 HW #4 Solutions
e and n + 1 > n, so the above inequality is true, which implies that the first inequality is true and that the terms are decreasing in absolute value. To see that the terms are going to zero, we just examine the limit lim n→∞ e1 n n = lim n→∞ n √ e n = 0, since lim[n]e = 1. Therefore, by the Alternating Series Test, the series ...
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Math 115 HW #4 Solutions - Colorado State University
www.math.colostate.eduin other words, we want to show that n+1 √ e n+1 < n √ e n. But certainly n+1 e < n e and n + 1 > n, so the above inequality is true, which implies that the first inequality is true and that the terms are decreasing in absolute value.
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Math 2260 Exam #1 Practice Problem Solutions
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Math 113 HW #6 Solutions - Colorado State University
www.math.colostate.eduTherefore, plugging in x = 0 gives the slope of the tangent line at (0,1): e 0 cos0−e 0 sin0 = 1−0 = 1. Therefore, by the point-slope formula, the equation of the tangent line is
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Math 113 HW #9 Solutions - Colorado State University
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