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Math 127: Chinese Remainder Theorem

math 127: Chinese Remainder TheoremMary Radcliffe1 Chinese Remainder TheoremUsing the techniques of the previous section, we have the necessary tools to solve congruences of the formax b(modn). The Chinese Remainder Theorem gives us a tool to consider multiple such , let s just ensure that we understand how to solveax b(modn).Example that 3x 7 (mod 10) on our previous work, we know that 3 has a multiplicative inverse modulo 10,namely 3 (10) 1. Moreover, (10) = 4, so the inverse of 3 modulo 10 is 33 27 7 (mod 10).Hence, multiplying both sides of the above equation by 7, we obtain3x 7 (mod 10) 7 3x 7 7 (mod 10) x 49 9 (mod 10)Hence, the solution isx 9 (mod 10).Example that 3x 6 (mod 12). oh. This time we don t have a multiplicative inverse to work with. So what to do?Well, let s take a look at what this would mean. If 3x 6 (mod 12), that means 3x 6 is divisibleby 12, so there is somek Zsuch that 3x 6 = 12k. Now that we re working in the integers, wecan happily divide by 3, and we thus obtain thatx 2 = 4k.

Example 5. Use the Chinese Remainder Theorem to nd an x such that x 2 (mod5) x 3 (mod7) x 10 (mod11) Solution. Set N = 5 7 11 = 385. Following the notation of the theorem, we have m 1 = N=5 = 77, m 2 = N=7 = 55, and m 3 = N=11 = 35. We now seek a multiplicative inverse for each m i modulo n i. First: m 1 77 2 (mod5), and hence an inverse to m 1 ...

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  Chinese, Math, Theorem, Remainder, Chinese remainder theorem, Remainder theorem, Math 127

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