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Math 2260 Exam #1 Practice Problem Solutions

Math 2260 Exam #1 Practice Problem Solutions 1. What is the area bounded by the curves y = x2 1 and y = 2x + 7? Answer: As we can see in the figure, the line y = 2x + 7 lies above the parabola y = x2 1 in the region we care about. Also, the points of intersection occur when 2x + 7 = x2 1 or, equivalently, when 0 = x2 2x 8 = (x 4)(x + 2), so the curves intersect when x = 4 and x = 2. Therefore, integrating top minus bottom over this region should yield the area between the curves: Z 4 Z 4. (2x + 7) x2 1 dx = 2x + 8 x2 dx . 2 2. 4. x3.. 2. = x + 8x . 3 2.. 64 16. = 16 + 32 4 16 +. 3 3. 64 8. = 48 + 12 . 3 3. 72. = 60 . 3. = 60 24. = 36. 100. So the area between the curves is 3 .. 2. What is the volume of the solid obtained by rotating the region bounded by the graphs of y = x, y = 2 x and y = 0 around the x-axis? . Answer: As we see in the figure, the line y = 2 x lies above the curve y = x in the region we care about.

Math 2260 Exam #1 Practice Problem Solutions 1.What is the area bounded by the curves y= x2 1 and y= 2x+ 7? Answer: As we can see in the gure, the line y= 2x+ 7 lies above the parabola y= x2 1 in the region we care about. Also, the points of intersection occur when 2x+ 7 = x2 1 or, equivalently, when 0 = x2 2x 8 = (x 4)(x+ 2);

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