Transcription of Math 241 Homework 12 Solutions - University of Hawaiʻi
{{id}} {{{paragraph}}}
Example: tourism industry
Math 241 Homework 12 Solutions - University of Hawaiʻi
math 241 Homework 12 SolutionsSection solid lies between planes perpendicular to thex-axis atx=0andx=4. Thecross-sections perpendicular to the axis on the interval0 x 4are squares whose diagonals runfrom the parabolay= xto the parabolay= xSolution From the picture we haves2+s2=(2 x)2 2s2=4x s2=2xSince the area of the square is given byA=s2=2xwe haveVolume=S402x dx=x2U40=161 Problem solid lies between planes perpendicular to thex-axis atx= 1andx=1. Thecross-sections perpendicular to thex-axis are circular disks whose diameters run from the parabolay=x2to the parabolay=2 We haveDiameter=2 2x2 Radius=1 x2 Since the area of a circle is given by r2we haveVolume=S1 1( 2 x2+ x4)dx= x 2 x33+ x55 RRRRRRRRRRR1 1= 2 3+ 5 +2 3 5 =2 4 3+2 5=30 20 +6 15=16 152 Problem base of a solid is the region between the curvey=2 sinxand the interval[0.]
Math 241 Homework 12 Solutions Section 6.1 Problem 1. The solid lies between planes perpendicular to the x-axis at x=0 and x=4. The cross-sections perpendicular to the axis on the interval 0 ≤x≤4 are squares whose diagonals run from the parabola y=− √ xto the parabola y= √ x Solution From the picture we have s2 +s2 =(2 √ x)2 ⇔ 2s2 ...
Tags:
Information
Domain:
Source:
Link to this page:
Please notify us if you found a problem with this document: