Transcription of Physics 1100: Electric Fields Solutions
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Physics 1100: Electric Fields Solutions
Questions:123456789 Physics 1100: Electric Fields Solutions1. What is the net force on charge A in each configuration shown below? The distances are r1 = cm and r2 = A is the target and charges B and C are sources. Charge B and A have the same sign, so they is, charge A feels a force FBA directed in the +i direction. Charge C and A have the opposite sign, so theyattract. That is, charge A feels a force FCA directed in the i direction. The situation is shown in the diagrambelow Since we know the exact direction of these forces we need only calculate the magnitude of these forces:andIn component vector form our two forces are FBA = +i[ N] and FCA = +i[ N].
Fnet = Q3Enet = (5 × 106)(827.283) = 4.1364 × 103 N. Since Q 3 is positive, F net and Enet are parallel, so F net also points along θ = 96.68° above horizontal. (b) To find the net force (magnitude and direction) on charge Q 2 due to charges Q 3 and Q 5 , we must first find
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