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Pre-Calculus Review Problems | Solutions 1 Algebra and ...

MATH 1110 (Lecture 002)August 30, 2013 Pre-Calculus Review Problems Solutions1 Algebra and GeometryProblem equations for the following lines inbothpoint-slope and slope-intercept form.(a) The line which passes through the point (1,2) having slope 4.(b) The line which passes through the points ( 1,1) and (2, 1).(c) The line parallel toy=12x+ 2, withy-intercept (0, 1).(d) The line perpendicular toy= 3x+ 1 which passes through the :(a) The point-slope form isy 2 = 4(x 1).Solving fory,y= 4(x 1) + 2= 4x 4 + 2= 4x 2,yields the slope-intercept form,y= 4x 2.(b) First, we compute the slope using the familiar rise-over-run formula,m= 1 12 ( 1)= point-slope form (using the first point) is,y 1 = 23(x+ 1),and solving foryyields the slope-intercept form,y= 23x+13.(c) The slope of our desired line is12, since parallel lines must have the same slope. The point-slope formis,y ( 1) =12(x 0),and the slope-intercept form isy=12x 1.

(c) The slope of our desired line is 1 2, since parallel lines must have the same slope. The point-slope form is, y ( 1) = 1 2 (x 0); and the slope-intercept form is y= 1 2 x 1: (d) The slope of our desired line is 1 3, since it must be the negative reciprocal of the slope any line to which it is perpendicular. The point-slope form is, y 0 = 1 ...

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  Line, Parallel, Perpendicular

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