Transcription of RS-Aggarwal-Solution-class-10-Maths-Chapter-5 …
{{id}} {{{paragraph}}}
Example: stock market
RS-Aggarwal-Solution-class-10-Maths-Chapter-5 …
RS aggarwal solutions for class 10 Maths Chapter 5 Arithmetic Progression Exercise 5A Page No: 257. Question 1: Show that each of the progressions given below is an AP. Find the first term, common difference and next term of each. (i) 9, 15, 21, 27, .. (ii) 11, 6, 1, -4, . (iii) -1, -5 /6 , -2 /3 , -1 /2 , . (iv) 2, 8, 18, 32, .. (v) 20, 45, 80, 125, . Solution: (i) 9, 15, 21, 27, . Here, 15 9 = 21 15 = 27 21 = 6 (which is constant). Common difference is 6. Or d = 6. Next term = 27 + d = 27 + 6 = 33. (ii) 11, 6, 1, -4, . Here, 6 11 = 1 6 = -5 -4 1 = -5 (which is constant). d (common difference) = -5. Next term = -4 5 = -9. (iii) -1, -5 /6 , -2 /3 , -1 /2 , . -5/6 - (-1) = 1/6 and -2/3 - (-5/6) = 1/6. d (common difference) = 1/6. Next term = -1/2 + 1/6 = -1/3. RS aggarwal solutions for class 10 Maths Chapter 5 Arithmetic Progression (iv) 2, 8, 18, 32.
RS Aggarwal Solutions for Class 10 Maths Chapter 5 Arithmetic Progression n -1 = 13 n = 13 + 1 = 14 Therefore, 3 is the 14th term. Question 13:
Loading..
Tags:
Information
Domain:
Source:
Link to this page:
Please notify us if you found a problem with this document: