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RS aggarwal Solutions for class 10 Maths chapter 5 Arithmetic Progression Exercise 5A Page No: 257. Question 1: Show that each of the progressions given below is an AP. Find the first term, common difference and next term of each. (i) 9, 15, 21, 27, .. (ii) 11, 6, 1, -4, . (iii) -1, -5 /6 , -2 /3 , -1 /2 , . (iv) 2, 8, 18, 32, .. (v) 20, 45, 80, 125, . Solution: (i) 9, 15, 21, 27, . Here, 15 9 = 21 15 = 27 21 = 6 (which is constant). Common difference is 6. Or d = 6. Next term = 27 + d = 27 + 6 = 33. (ii) 11, 6, 1, -4, . Here, 6 11 = 1 6 = -5 -4 1 = -5 (which is constant). d (common difference) = -5. Next term = -4 5 = -9. (iii) -1, -5 /6 , -2 /3 , -1 /2.

RS Aggarwal Solutions for Class 10 Maths Chapter 5 Arithmetic Progression-47 = 18 + (n – 1)(-5/2)-47 - 18 = (n - 1)(-5/2) n = 27 There are 27 terms. Question 10: Which term of the AP 3, 8, 13, 18, … is 88? Solution: Let nth term is 88. AP is 3, 8, 13, 18, … Here, First term = a = 3 Common difference = d = 8 – 3 = 5 nth term of AP is a n

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