Transcription of Section 2.7 Related Rates (Word Problems)
{{id}} {{{paragraph}}}
Section Related Rates (Word Problems) The idea is to compute the rate of change of one quantity in terms of the rate of change of anotherquantity.(pg. 127) Example: Air is being pumped into a spherical balloon so that its volume increases at a rateof 100 cm3 / s. How fast is the radius of the balloon increasing when the diameter is 50 cm?Step 1 & 2: Draw a picture and list what you (units tell variables)d=2r=50cmr=25cmFind: drdtStep 3: Write an equation relating the r3 Step 4: Take derivatives of both sides (implicitly).ddt V =ddt 43 r3 dVdt=43 3r2 drdt=4 r2drdtStep 5 Solve for what you are trying to r2 dVdtStep 6 Substitute in what you 25 2 100=25 25 2=125 Step 7: Check the cms125 cmsNote: There are 5 very nice examples worked out in the textbook.
Section 2.7 Related Rates (Word Problems) The idea is to compute the rate of change of one quantity in terms of the rate of change of another quantity. (pg. 127) Example: Air is being pumped into a spherical balloon so that its volume increases at a rate of 100 cm 3 / s. How fast is the radius of the balloon increasing when the
Domain:
Source:
Link to this page:
Please notify us if you found a problem with this document:
{{id}} {{{paragraph}}}