Transcription of Smith Chart Problems - University of Houston
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Smith Chart Problems - University of Houston
:1 lengthlineshownhasacharacteristicimpedan ceof50 andisterminatedwithaloadimpedanceofZL=5+ j25 .(a)LocatezL=ZLZ0=0:1+j0 (b)Whatistheimpedanceat`=0:1 ?Sincewewanttomoveawayfromtheload( ,towardthegenerator),readread0:074 onthewavelengthstowardgeneratorscaleanda dd`=0:1 toobtain0:174 ec-tioncoe cientmagnitudecircleatz=0:38+j1:88:Hence Z=zZ0=50(0:38+j1:88)=19+94 .(c)WhatistheVSWR ontheline?FindVSWR=zmax=13onthehorizonta llinetotherightofthechart' (d)Whatis L?Fromthereflectioncoefficientscalebelow thechart, ndj Lj=0 , ndtheangleof L=126:5 .Hence L=0:855ej126:5 .(e)Whatis at`=0:1 fromtheload?Notethatj j=j Lj=0 ectioncoe cientfromtheangleofreflectioncoefficient scaleas55:0 .Hence =0:855ej55:0 . + = ..TG ..TG +maxVSWR13z== = = = = = =VSWR 13=LZLZ525[]j=+ 0Z50= =l01 Problem :0,ZL=zL=0:2 j0:2 :(a)Whatiszat`= 4=0:25 ?
Smith c hart for lo cation of p oin t. (b) What is the line imp edance 2: 5cm from the load? Note that = c f 3 10 10 cm/sec 3 10 9 Hz 10 cm: Since w e are going to mo v e to w ard the generator (a a y from the load), at the normalized load p osition, rst read 0: 217 on w a ve-lengths to w ard genera tor scale. Then add 2.5 cm/10 cm = 0: 25 to ...
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