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StoichiometryStoichiometry - Weebly
Copyright Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Manual chemistry : Matter and Change Chapter 11 209 StoichiometryStoichiometrySOLUTIONS MANUALCHAPTER11 Section Defining Stoichiometrypages 368 372 Practice Problemspages 371 372 1. Interpret the following balanced chemical equa-tions in terms of particles, moles, and mass. Show that the law of conservation of mass is N2(g) 3H2(g) 2NH3(g)1 molecule N2 3 moleculesH2 2 molecules NH31 mole N2 3 moles H2 2 moles NH3 Mass:N2: (2 mol)( g/mol) g3H2: (6 mol)( g/mol) g2NH3: (2 mol)( g/mol) (6 mol)( g/mol) g N2 g H2 0 g g reactants g productsb. HCl(aq) KOH(aq) KCl(aq) H2O(l)1 molecule HCl 1 formula unit KOH 1 formula unit KCl 1 molecule H2O1 mole HCl 1 mole KOH 1 mole KCl 1 mole H2 OMass:HCl: (1 mol)( g/mol) (1 mol)( g/mol) gKOH: (1 mol)( g/mol) (1 mol)( g/mol) (1 mol)( g/mol) gKCl: (1 mol)( g/mol) (1 mol)( g/mol) gH2O: (2 mol)( g/mol) (1 mol)( g/mol) g HCl g KOH g KCl g g reactants g productsc.
StoichiometryStoichiometry CHAPTER 11 SOLUTIONS MANUAL Section 11.1 Defining Stoichiometry ... following balanced chemical equations. a. 4Al(s) 3O 2 (g) → 2Al 2 O 3 (s) 4 mol Al _ 3 mol O 2 3 mol O 2 __ 2 mol Al 2O 3 2 mol Al 2O 3 __ 4 mol Al ... 212 Chemistry: Matter and Change • Chapter 11 Solutions Manual CHAPTER 11 SOLUTIONS MANUAL c.
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