Example: tourism industry
Chapter 5: Normal Probability Distributions - Solutions
b.Find the mean of the sampling distribution of sample means. x =63 c.Find the standard deviation of the sampling distribution of sample means. ˙ x = ˙ p n = 11 p 100 =1:1 d.What is the probability that the mean of a sample is greater than $74? (hint: rst nd the z-score) z= ˙ = z= ˙ = ˙ =
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