Computer Organization and Architecture Arithmetic & Logic …
01: End of a string of 1s, so add the multiplicand to the left half of the product (A). 10: Beginning of a string of 1s, so subtract the multiplicand from the left half of the product (A). 11: Middle of a string of 1s, so no arithmetic operation. • Then shift A, Q, bit Q-1 right one bit using an arithmetic shift
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