DIFFERENTIATING UNDER THE INTEGRAL SIGN
DIFFERENTIATING UNDER THE INTEGRAL SIGN 3 so (2.4) Z 1 0 xe txdx= 1 t2: Di erentiate both sides of (2.4) with respect to t, again using (1.2) to handle the left side. We get Z 1 0 x2e txdx= 2 t3: Taking out the sign on both sides, (2.5) Z 1 0 x2e txdx= 2 t3: If we continue to di erentiate each new equation with respect to ta few more times, we ...
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