Even/odd proofs: Practice problems Solutions
Since the sum of two odd numbers is even (by Problem 1), s+t = p2 is even. Hence p, must be even as well (by Problem 2). Therefore p = 2h for some h 2Z, by the de nition of an even integer. 2. Math 347 Worksheet on \Even/odd" Proofs Solutions A.J. Hildebrand
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