Integration and Differential Equations
26 Integration and Differential Equations Cutting out the middle leaves dy dx = 6x3 + c 1. Integrating this, we have y(x) = Z dy dx dx = Z 6x3 +c 1 dx = 6 4 x4 + c 1x + c 2. So the general solution to equation (2.8) is y(x) = 3 2 x4 + c 1x +c 2. In practice, rather than use the same letter with different subscripts for different arbitrary
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