Integration by Partial Fractions
dx = ˆ −x −3 x2 +1 + 1 x −1 dx = − ˆ x x2 +1 dx −3 ˆ 1 x2 +1 dx + ˆ 1 x −1 dx = − 1 2 ln(x2 +1)−3tan−1(x) +ln|x −1|+C Where the first two integrals are solved with a u-substitution and trigonometric substitution, respectively. Practice Problems Try some of the problems below. If you get stuck, don’t worry! There are ...
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