Integration by parts
1 3 e3x. Then, using the formula for integration by parts, Z x2e3x dx = 1 3 e3x ·x2 − Z 1 3 e3x ·2xdx = 1 3 x2e3x − Z 2 3 xe3x dx. The resulting integral is still a product. It is a product of the functions 2 3 x and e3x. We can use the formula again. This time we choose u = 2 3 x and dv dx = e3x. Then du dx = 2 3 and v = Z e3xdx = 1 3 ...
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