Math 2260 Exam #1 Practice Problem Solutions
Math 2260 Exam #1 Practice Problem Solutions 1.What is the area bounded by the curves y= x2 1 and y= 2x+ 7? Answer: As we can see in the gure, the line y= 2x+ 7 lies above the parabola y= x2 1 in the region we care about. Also, the points of intersection occur when 2x+ 7 = x2 1 or, equivalently, when 0 = x2 2x 8 = (x 4)(x+ 2);
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Math 2260 Exam #1 Practice Problem Solutions
www.math.colostate.eduMath 2260 Exam #1 Practice Problem Solutions 1.What is the area bounded by the curves y= x2 1 and y= 2x+ 7? Answer: As we can see in the gure, the line y= 2x+ 7 lies above the parabola y= x2 1 in the region we care about.
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Math 113 HW #6 Solutions - Colorado State University
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Math 115 HW #4 Solutions - Colorado State University
www.math.colostate.eduin other words, we want to show that n+1 √ e n+1 < n √ e n. But certainly n+1 e < n e and n + 1 > n, so the above inequality is true, which implies that the first inequality is true and that the terms are decreasing in absolute value.
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Math 113 HW #9 Solutions - Colorado State University
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Math 215 HW #6 Solutions - Colorado State University
www.math.colostate.edu7. Problem 3.2.8. The methane molecule CH 4 is arranged as if the carbon atom were at the center of a regular tetrahedron with four hydrogen atoms at the vertices. If vertices are placed at (0,0,0), (1,1,0), (1,0,1), and (0,1,1)—note that all six edges have length √ 2,
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Math 2260 Exam #3 Practice Problem Solutions
www.math.colostate.eduMath 2260 Exam #3 Practice Problem Solutions 1.Does the following series converge or diverge? Explain your answer. X1 n=0 2n 3n+ n3: Answer: Since 3 n+ n3 >3 for all n 1, it follows that 2n 3n+ n3 < 2n 3n = 2 3 n: Therefore, X1 n=0 2n 3n+ n3 < X1 n=0 2 3 n = 1 1 2 3 = 3: Hence, the given series converges. 2.Does the following series converge or ...