Synchrotron Radiation - NASA

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Since (dE/dt) is a Lorentz invariant, we recover the formula (8). Recalling that c2 = (µ0ε0)−1, let us rewrite this in the following way − dE dt = 2 e4 6πε2 0c4m2e! v c 2 c B2 2µ0 γ2 sin2 θ (12) The quantity in the first set of round brackets on the right-hand side of (8) is the Thomson cross-section σT. Therefore − dE dt ...