The Inverse Laplace Transform
532 The Inverse Laplace Transform! Example 26.5: In exercise25.1e on page 523, you found thatthe Laplacetransformof the solution to y′′ + 4y = 20e4t with y(0) = 3 and y′(0) = 12 is Y(s) = 3s2 −28 (s −4). s2 +4 The partial fraction expansion of this is Y(s) = 3s2 −28 (s − 4) s2 +4 A s − + Bs +C s2 +4 for some constants A, B and C .
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