Solving Equations With
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Algebra 1 - Solving Equations by Cross Multiplication
msthibeault.weebly.comSolving Equations by Cross Multiplication Solve each proportion. 1) n 5 = 6 7 2) 4 8 = v 6 3) 9 7 = k 2 4) 2 10 = 10 x 5) 7 5 = 6 n 6) 4 9 = 9 m 7) b 9 = 10 3 8) 3 6 = 5 r 9) 5 4 = p 5 10) x 10 = 9 6-1-©N 92041 73o CKaumtBaw xSSovf kt0w ta gr oe7 FL vL mCX.p J 4A6lXlQ Lr viWg4hEt Msn dr 2eQs1e sr 7vvesdX.6 t pMFaYdLeH bwgiFtph m iI wnxflipn ...
Solving Quadratic Equations - Metropolitan Community …
www.mcckc.eduSOLVING QUADRATIC EQUATIONS A quadratic equation in is an equation that may be written in the standard quadratic form if . There are four different methods used to solve equations of this type. Factoring Method If the quadratic polynomial can be …
Solving Radical Equations - Metropolitan Community …
www.mcckc.eduSolving equations requires isolation of the variable. Equations that contain a variable inside of a radical require algebraic manipulation of the equation so that the variable “comes out” from underneath the radical(s). This can be accomplished by raising both sides of the equation to the “nth” power, where n is the
Solving One-Step Equations 1 - McNabbs
karen.mcnabbs.orgSolving One-Step Equations 1 You must show your work to get credit!! Check your answer. Adding and Subtracting 1) y 6 20 2) x 10 12 3) 12 z 15 14 22 3 4) 2 n 16 5) a 4 14 6) m 5 10 14 10 -5 7) 4 b 1030 8) c 25 9) x 60 20 26 15 80 10) g 16 4 11) x 15 20 12) w 14 10
Solving Quadratic Equations: Square Root Law
www.lavc.eduElementary Algebra Skill Solving Quadratic Equations: Square Root Law Solve each equation by taking square roots. 1) r2 = 96 2) x2 = 7 3) x2 = 29 4) r2 = 78 5) b2 = 34 6) x2 = 0 7) a2 + 1 = 2 8) n2 − 4 = 77 9) m2 + 7 = 6 10) x2 − 1 = 80 11) 4x2 − 6 = 74 12) 3m2 + 7 = 301 13) 7x2 − 6 = 57 14) 10x2 + 9 = 499 15) (p − 4)2 = 16 16) (2k − 1)2 = 9
Solving Multi-Step Equations - cdn.kutasoftware.com
cdn.kutasoftware.comSolving Multi-Step Equations Date_____ Period____ Solve each equation. 1) 4 n − 2n = 4 2) −12 = 2 + 5v + 2v 3) 3 = x + 3 − 5x 4) x + 3 − 3 = −6 5) −12 = 3 − 2k − 3k 6) −1 = −3r + 2r 7) 6 = −3(x + 2) 8) −3(4r − 8) = −36 9) 24 = 6 ...