Example: quiz answers

9.2 Solving Quadratic Equations by Completing the Square

2001 McGraw-Hill Companies679 Solving Quadratic Equations by Completing the a Quadratic equation by the squareroot a Quadratic equation by completingthe a geometric application involving aquadratic equationIn Section , we solved Quadratic Equations by factoring and using the zero productrule. However, not all Equations are factorable over the integers. In this section, we willlook at another method that can be used to solve a Quadratic equation, called the squareroot , we will solve a special type of equation using the factoring methodof Chapter Equations by FactoringSolve the Quadratic equation x2 16by write the equation in standard form:x2 16 0 Factoring, we have(x 4)(x 4) 0 Finally, the solutions arex 4orx 4or 4 Example 1 NOTEHer

SOLVING QUADRATIC EQUATIONS BY COMPLETING THE SQUARE SECTION 9.2 683 © 2001 McGraw-Hill Companies Completing the Square to Solve an Equation Solve x2 5x 3 0 by ...

Tags:

  Solving, Equations, Quadratic, Completing, Solving quadratic equations by completing the

Information

Domain:

Source:

Link to this page:

Please notify us if you found a problem with this document:

Other abuse

Advertisement

Transcription of 9.2 Solving Quadratic Equations by Completing the Square

1 2001 McGraw-Hill Companies679 Solving Quadratic Equations by Completing the a Quadratic equation by the squareroot a Quadratic equation by completingthe a geometric application involving aquadratic equationIn Section , we solved Quadratic Equations by factoring and using the zero productrule. However, not all Equations are factorable over the integers. In this section, we willlook at another method that can be used to solve a Quadratic equation, called the squareroot , we will solve a special type of equation using the factoring methodof Chapter Equations by FactoringSolve the Quadratic equation x2 16by write the equation in standard form.

2 X2 16 0 Factoring, we have(x 4)(x 4) 0 Finally, the solutions arex 4orx 4or 4 Example 1 NOTEHere, we factor thequadratic member of theequation as a difference YOURSELF 1 Solve each of the following Quadratic Equations .(a)5x2 180(b)x2 25 The equation in Example 1 could have been solved in an alternative fashion. We could haveused what is called the Square root , given the equationx2 16we can write the equivalent statementx orx This yields the solutionsx 4orx 4or 4 This discussion leads us to the following general sure to include boththe positive and the negativesquare roots when you use thesquare root , FUNCTIONS, ANDINEQUALITIES 2001 McGraw-Hill CompaniesExample 2 further illustrates the use of this the Square Root MethodSolve each equation by using the Square root method.

3 (a)x2 9By the Square root property,x orx 3 3or 3 (b)x2 17 0 Add 17 to both sides of the 17so x or or , (c)2x2 3 02x2 3x2 x x or(d)x2 1 0x2 1x x ior i 1 1 162 162A32321171171171171919 Example 2 NOTEIf a calculator wereused, (rounded tothree decimal places).117 Example 2(d ) we seethat complex-number solutionsmay x2 k, when kis a complex number, thenx orx 2k2kRules and Properties: Square Root PropertyWe can also use the approach in Example 2 to solve an equation of the form(x 3)2 16 CHECK YOURSELF 2 Solve each equation.

4 (a)x2 5(b)x2 2 0(c)3x2 8 0(d)x2 9 0 SOLVINGQUADRATICEQUATIONS BYCOMPLETING 2001 McGraw-Hill CompaniesUsing the Square Root MethodUse the Square root method to solve each equation.(a)(x 5)2 5 0(x 5)2 5x 5 x 5 or 5 (b)3(y 1)2 2 03(y 1)2 2(y 1)2 y 1 y 1 orThe approximate solutions are , . 3 163 3 163163A2323151515 Example 3 NOTEThe two solutionsand areabbreviated as 5 . Using acalculator, we find theapproximate solutions , .155 155 15 NOTEWe have solved for yand rationalized we combine the terms onthe right, using the commondenominator of 1213 12 1313 13 163 CHECK YOURSELF 3 Using the Square root method, solve each equation.

5 (a)(x 2)2 3 0(b)2(x 1)2 1As before, by the Square root property we havex 3 4 Subtract 3 from both sides of the for xyieldsx 3 4which means that there are two solutions:x 3 4orx 3 4 1 7or 1, 7 Not all Quadratic Equations can be solved directly by factoring or using the Square rootmethod. We must extend our Square root method is useful in this process because any Quadratic equation can bewritten in the form(x h)2 kwhich yields the solutionx h 1kNOTEIf (x h)2 k, thenx h andx h 1k1k682 CHAPTER9 QUADRATICEQUATIONS, FUNCTIONS, ANDINEQUALITIES 2001 McGraw-Hill CompaniesThe process of changing an equation in standard formax2 bx c 0to the form(x h)

6 2 kis called the method of Completing the Square ,and it is based on the relationship betweenthe middle term and the last term of any perfect- Square s look at three perfect- Square trinomials to see whether we can detect a pattern:x2 4x 4 (x 2)2(1)x2 6x 9 (x 3)2(2)x2 8x 16 (x 4)2(3)Note that in each case the last (or constant) term is the Square of one-half of the coefficientof xin the middle (or linear) term. For example, in equation (2),x2 6x 9 (x 3)2of this coefficient is 3, and ( 3)2 9, the this relationship for yourself in equation (3).

7 To summarize, in perfect- Square trino-mials, the constant is always the Square of one-half the coefficient of are now ready to use the above observation in the solution of Quadratic Equations bycompleting the Square . Consider Example Completing the Square to Solve an EquationSolve x2 8x 7 0 by Completing the , we rewrite the equation with the constant on the right-hand side:x2 8x 7 Our objective is to have a perfect- Square trinomial on the left-hand side. We know that wemust add the Square of one-half of the xcoefficient to complete the Square .

8 In this case, thatvalue is 16, so now we add 16 to each side of the 8x 16 7 16 Factor the perfect- Square trinomial on the left, and combine like terms on the right to yield(x 4)2 23 Now the Square root property yieldsx 4 Subtracting 4 from both sides of the equation givesx 4 or 4 As decimals, these solutions are approximated by , .123123123 NOTEN otice that thisrelationship is true onlyif theleading, or x2, coefficient is will be important 4 NOTE12 8 4 and 42 16 NOTEWhen you graph therelated function,y x2 8x 7, you will notethat the xvalues for the xintercepts are just below 1 andjust above 9.

9 Be certain thatyou see how these points relateto the exact solutions, 4 and 4 .123123 CHECK YOURSELF 4 Solve x2 6x 2 0by Completing the that if(x h)2 k, then x h .1kSOLVINGQUADRATICEQUATIONS BYCOMPLETING 2001 McGraw-Hill CompaniesCompleting the Square to Solve an EquationSolve x2 5x 3 0 by Completing the 5x 3 0 Add 3 to both 5x 3 Make the left-hand side a perfect 5x 3 Take the Square root of both Solve for orThe approximate solutions are , . 5 1372 5 1372137252374 x 52 2 52 2 52 2 Example 5 Completing the Square to Solve an EquationSolve x2 4x 13 0 by Completing the 4x 13 0 Subtract 13 from both 4x 13 Add to both 4x 4 13 4 Factor the left-hand side.

10 (x 2)2 9 Take the Square root of both 2 Simplify the 2 x 2 3ix 2 3ior 2 3i 19i1 9B12 (4)R2 Example 6 CHECK YOURSELF 5 Solve x2 3x 7 0by Completing the YOURSELF 6 Solve x2 10x 41 Equations have nonreal complex solutions, as Example 6 the Square of one-half of the xcoefficient to bothsides of the equation. Note that12 5 52 NOTEN otice that the graph ofy x2 4x 13 does notintercept the 7 illustrates a situation in which the leading coefficient of the Quadratic mem-ber is not equal to 1. As you will see, an extra step is , FUNCTIONS, ANDINEQUALITIES 2001 McGraw-Hill CompaniesCompleting the Square to Solve an EquationSolve 3x2 6x 7 0 by Completing the 6x 7 0 Add 7 to both 6x 7 Divide both sides by 2x Now, complete the Square on the 2x 1 1 The left side is now a perfect Square .


Related search queries