Example: air traffic controller

Chapter 14

Chapter14 MODULATIONINTRODUCTIONA swehaveseeninpreviousthreechapters, ,thesourceinformationisimpresseduponacar rier-wave(essentiallyasinusoidofacertain frequency) ( ,audio,voltagepulsetraincarryingdigitali nformation) forexample,therepresentationofsampledsig nalsbytheamplitude, (2,6,9)thatwecanwritethissinusoidalcarri ersignalas:c(t)=Acos(2 fct+ )( )Here,Aiscalledtheamplitudeand ,dataareusedtomodulateorchangeitsamplitu de,frequency, , (digitalmodulation) ,wealsodescribeaspecialcaseofdigitalmodu lationthatisveryimportantfortransmission ofinformationusingmodems quadratureamplitudemodulation(QAM) atechniquecalled675676 ThePhysicalLayerofCommunicationsSystemso rthogonalfrequencydivisionmultiplexing(O FDM).

In analog modulation, the characteristics of the modulated sinusoid (such as amplitude, frequency or phase) can take a continuum of values depending on the source of the information. The two common forms of analog modulation are amplitude modulation (AM) and frequency modulation (FM) which is specific form of more general angle modulation ...

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Transcription of Chapter 14

1 Chapter14 MODULATIONINTRODUCTIONA swehaveseeninpreviousthreechapters, ,thesourceinformationisimpresseduponacar rier-wave(essentiallyasinusoidofacertain frequency) ( ,audio,voltagepulsetraincarryingdigitali nformation) forexample,therepresentationofsampledsig nalsbytheamplitude, (2,6,9)thatwecanwritethissinusoidalcarri ersignalas:c(t)=Acos(2 fct+ )( )Here,Aiscalledtheamplitudeand ,dataareusedtomodulateorchangeitsamplitu de,frequency, , (digitalmodulation) ,wealsodescribeaspecialcaseofdigitalmodu lationthatisveryimportantfortransmission ofinformationusingmodems quadratureamplitudemodulation(QAM) atechniquecalled675676 ThePhysicalLayerofCommunicationsSystemso rthogonalfrequencydivisionmultiplexing(O FDM).

2 , , (smallerwavelengths) , , ,thistimetoanintermediatefrequency(IF) (multiplexing). , ,thecharacteristicsofthemodulatedsinusoi d(suchasamplitude,frequencyorphase) (AM)andfrequencymodulation(FM) , , , EncoderChannel EncoderModulatorChannelDe-modulatorChann el DecoderSource [1]. ! ! , , , , (1G)oranalogcellularsystemsintheUSA, ,webrieflyconsideredamodelofadigitalcomm unicationsystemwherewehaveasource,asourc eencoder,andachannelencoderonthetransmit tersideandthecorrespondingchanneldecoder , , , ,ifthealphabetisbinary,thetwopossiblesym bolsare0and1andinformationissimplyalongs equenceof0 sand1 binary digitalsignalrepresentsthe zerosymbol usingaspecificsignalthatlastsforaduratio nofTssecondsandthe onesymbol , , ,mostsystemsareconstructedsuchthatM= , ,ifm1,m2,m3,andm4arethesymbolsofa4-arysy stem,wecanassociatethe dibit 00tom1,01tom2, (expressedinunitsofbaud).

3 Thebitrate(ifM=2k) s,thenthesymbolrateis1 (k=4oritisaM=16-aryalphabet) ,themessageismappedtotheamplitude,freque ncy,phase(oracombinationofthese) , , , , , (QAM).Inanalogmodulationwewereinterested intheSNR,butrecallfromChapter10thatindig italmodulationweareinterstedinthebiterro rrate(BER)asafunctionoftheratiooftheener gyperbit(Eb)tothevalueofthenoisePSD(N0) ,likeanalogmodulationwewouldliketomaximi zetheefficiencywithwhichweusetheavailabl ebandwidthindigitalmodulationwequantifyt hespectralefficiencyfortheamountofbandwi dthWrequiredtotransmitatagivendatarateRq uantifiedas = , ,therearetradeoffsbetweentheBERforagiven EbN0and .690 ThePhysicalLayerofCommunicationsSystemst imetimeAmplitudeAmplitude100% Depth50% Depth0timeAmplitudetimeAmplitude10010010 0100 BasebandBasebandTS2TS3 , signalconstellation.

4 Withasignalconstellation, ,thealphabethastwovalues 0 and 1. InASK,a 0 ismappedtooneamplitudevalueanda 1 ,a 0 ismappedtoonefrequencyvalueanda 1 ,a 0 ismappedtoonephasevalueanda 1 , (BASK).InBASK, ,si(t)=Aicos(2 fct+ ),0 t Tsfori=1,2( )Thetransmitterwilltransmits1(t)whentheb itiszeroands2(t) ,werefertothemodulationschemeashaving100 % (wherethetwoamplitudevaluesareAand0) ,wesaythatthemodulationdepthis50%. , zero bitisgivenby:Ezero= Ts0s21(t)dt=A21 Ts0cos2(2 fct+ )dt=A212 Ts0[1+cos(2 (2 fc)t+2 )]dt A212Ts( )Theapproximationisanequalityiffc=kTsand isacloseapproximationiffc$ one bitissimilarlyequalto:Eone=A222Ts( )Theaverageenergyperbitisgivenby:Eb,av=T s4[A21+A22]( )Hereweassumethatthenumberof 0 sandthenumberof 1 ,theaverageenergyperbitcanbecalculatedto beEb=A2Ts4andEb= , ( ).

5 Thebasebandsignalcanberecoveredattherece iverusingthesametechniquesasAM(enveloped etectionorcoherentdetection). , , someexamplesaretelevisionremotes, (BFSK).InBFSK, ,si(t)=Acos(2 fit),0 t Tsfori=1,2( ) (t)whenthebitiszeroands2(t) (t)ands2(t)whichinvolvesmultiplicationof thetwosignalsandintegrationoveronesymbol periodgivenby: Ts0s1(t)s2(t)dt=A2 Ts0cos(2 f1t)cos(2 f2t)dt=A22 Ts0[cos(2 (f1 f2)t)+cos(2 (f1+f2)t)]dt( )Theterm cos(2 (f1+f2)t) cos(2 (f1 f2)t) ,orthogonalFSKensuresthatthereisnocorrel ationbetweens1(t)ands2(t),thatis: Ts0s1(t)s2(t)dt=0( )InthecaseoforthogonalFSK,f1 f2=1 Tssothattheintegrationin cos(2 (f1 f2)t) (OFDM)lateroninthischapter( ).

6 AswesawinthecaseofBASK,theenergyperbitin BFSK(forbotha 0 anda 1 ) , , ,anFSKsignal,likeFM, (Chapter10).RecallthataManchesterpulseco nsistsoftwo half (liketheAdvancedMobilePhoneSystem AMPS).Recently,FSKhasfoundapplicationsin lowpowerwirelessnetworkslikeBluetooth, (BPSK).InBPSK, ,si(t)=Acos(2 fct+ i),0 t Tsfori=1,2( )Thetransmitterwilltransmits1(t)whentheb itiszeroands2(t) radians,themaximumpossiblephasedifferenc ebetweenthetwobitsis .Itiscommontoassumethat 1=0and 2= inwhichcase,thetwosignalswillbe:s1(t)=Ac os(2 fct),0 t Tss2(t)=cos(2 fct+ )= Acos(2 fct),0 t Ts( ) ,wecanseethatthereisareversalofphasewhen thebitchangesandso, (t)= s2(t)andwecanviewBPSKasBASK whereA1=AandA2= , ,BPSK isequivalenttoantipodalorbipolarsignalin gwithnon-return-to-zero(NRZ) , ,BPSK signals,likephasemodulation, , , ,althoughdifferentmodulationschemesareus eddependingonthetransmissionrate, dualBPSK fortransmissionsfromthecellphonetowertom obiledevices(downlink).

7 Here,therearetwoBPSK signals, ,thesourceproducesoneofMsymbolsmifori=1, 2,3, , (t) , :si(t)=Aicos(2 fct+ ),0 t Tsfori=1,2,3, ,M( ) (2i 1 M) , , (inthiscased) 3, 1, :s1(t)=cos(2 fct+ ),0 t Tss2(t)= cos(2 fct+ ),0 t Tss3(t)=3cos(2 fct+ ),0 t Tss4(t)= 3cos(2 fct+ ),0 t TsNotethatonceagain, , :si(t)=Acos[2 fct+2 (i M2)!ft],0 t Tsfori=1,2,3, ,M( )TheMfrequencieswillbefc+(i M2)!ffori=1,2,3, , ! , :si(t)=Acos(2 fct+ i),0 t Tsfori=1,2,3, ,M( )Thephase iistypicallygivenby i=2 M(i 1)+ (CDMA anddigitalTDMAinNorthAmerica). , 2, ,3 4,thefourphaseswillbe 4,3 4,5 4and7 4-QPSK,avariationofQPSK,thesymbolsarepic kedalternativelyfromthesetwoschemes(cons tant=0andconstant= 4) (multiplepositiveandnegative)amplitudesa reusedwiththetwophase-shiftedcarriers,th emodulationschemeiscalledquadratureampli tudemodulation(QAM).

8 :si(t)=Ai,Icos(2 fct)+Ai,Qsin(2 fct),0 t Tsfori=1,2,3, ,M( ) :si(t)=Aicos(2 fct+ i),0 t Tsfori=1,2,3, ,M( )696 ThePhysicalLayerofCommunicationsSystemsw hereAi= A2i,I+A2i,Qand i= tan 1(Ai,QAi,I).Soitispossibleforustothinkof QAMasamixofbothamplitudeandphaseshiftkey ingsincethemessagemiismappedtoacarrierwi thamplitudeAiandphase ,itiscommoninM-QAMtopickthein-phaseandqu adrature-phaseamplitudessuchthattheyareo ftheform(2i 1 M) , ,recently, , , [1],[2].Inmostcases,weassumethattherecei vedsignalisonlycorruptedbyadditivewhiteG aussiannoise(AWGN) (t)forsomei 1,2,3, ,M,thereceivedsignalwillbe:r(t)=si(t)+n( t),0 t Ts( )Thegoalofthereceiveristodeterminewhatsi (t)wastransmittedgiventhatr(t) (t)was, ,r(t)iscorruptedbynoiseanditispossibleth atthereceiverwillsometimesdeterminethatt hetransmittedsignalwassj(t)wherej(=iwhen si(t) (Eb) (100% modulation ) 0 andabit 1.)

9 ,eventhevisualdifferencebetweenthe 0 bitandthe 1 ,whoafteralldonotsensevoltagesthatwell:- ).Asthereceivedsignalgetsnoisier, Tx signal with two bitsBASK Rx signalBASK Rx signalBASK Rx signalBASK Rx signalBASK Tx signal with two Rx signalBASK Rx signalEb/N0=10dBEb/N0=7dBEb/N0= :r(t)=Aicos(2 fct)+n(t),0 t Ts( )TorecoverthenumberAi, (a).Thatis,thereceivercomputes:Z= Ts0r(t)cos(2 fct)dt= Ts0 Aicos2(2 fct)dt+ Ts0n(t)cos(2 fct)dt=Ai2+ Ts0n(t)cos(2 fct)dt=Ai2+n( )wheren= Ts0n(t)cos(2 fct)dtisaGaussianrandomvariable(withzero meanandavariancethatisafunctionofN02) with threshold(a) BASK/BPSK receiverCompare with thresholds(a) MPSK/QAM receiverr(t)cos(2 fct)sin(2 fct)ZZ1Z2Ts0 TsTs00r(t)cos(2 fct) , ,undernoise-freeconditions, , 0 whena 1 ,fromacommonsenseperspective,ifZisaboveA i4,thereceiverdecidesthata 0 wastransmittedanda 1 , ,thereceiverneedstodetectwhetherthephase is0 or180.

10 Asimplewayofdeterminingthiswouldbetoperf ormthefollowingcomputation:Z= Ts0r(t)cos(2 fct)dt( ) ,thecomputednumberZwillbeasfollows:Z={A Ts0cos2(2 fct)dt+ Ts0n(t)cos(2 fct)dtifthephaseis0 A Ts0cos2(2 fct)dt+ Ts0n(t)cos(2 fct)dtifthephaseis180 ( )MODULATION699 Notethatinthenoiselesscase(n(t)=0),Zwill havealargepositivevalue(A2)whenthephasei s0 andalargenegativevalue( A2)whenthephaseis180 . ,thereceiverdecidesthatthe 0 bitwastransmittedifZispositiveandthe 1 ( ). ,thevalueofZmaybemovedtowardszeroandinso mecases, , :r(t)=Acos(2 fct+ i)+n(t)( ) ,thereceiverwillmultiplythereceivedsigna lbybothasineandacosinecarrier(thatareloc allygenerated) (b).}


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