Transcription of Infinite Algebra 1 - Parallel & Perpendicular Slopes ...
1 E p2r0_1s7f xKZultzao ^Seo\fitSwXaArde] O \AwlulN `r_iRgrhetMsJ Rr]eIsXeXr] D pMSasdleM ]wpiqtTh_ UIMnPffiSnWiLtFey YAWlmgoeabnrXa\ by Kuta Software LLCG eometry Summer Work - Week #4 Parallel & Perpendicular Slopes & Equations of LinesName_____ ID: 1 Date_____ Q p2o0D1j7S DK[ukttaB USio\fttHweaTrbeD Y WAvlKlD vrhisg[hHt`sG the slope of each ) xy2) xyFind the slope of the line through each pair of ) (2, -10), (8, -16)4) (-17, -5), (15, -13)Find the slope of each ) y = 95x + 56) y = 5 Find the slope of a line Parallel to each given ) y = -52x - 28) y = -x - 5 b s2J0y1I7A HKuuatJaQ sSRoyfTtywHaxrieh _ RAHlKlb brJiOglhqtisD WrLeJsAearWvjevd`.X g TMTaMdYed UwmiptHht WIXnTfri^nXiWtjew wAKllgEeObIrZad by Kuta Software LLC-2-9) y = 12x + 510) y = -13x - 411) 7x - 5y = 2012) 5x + y = 3 Find the slope of a line Perpendicular to each given ) x - y = 014) x + 2y = 6 Write the slope-intercept form of the equation of the line ) through: (4, -1), Parallel to y = -34x16) through: (4, 5), Parallel to y = 14x - 417) through: (-2, -5), Parallel to y = x + 318) through: (4, -4), Parallel to y = 319) through: (-3, -3), perp.
2 To y = -38x - 220) through: (0, -4), perp. to y = -32x + 121) through: (1, -3), perp. to y = -x22) through: (2, 4), perp. to y = -x + 5 [ N2x0P1R7_ iK]uvtla^ ^SqoBfct[wFasrPeo R pANlIlL xrvinglhNtssv Wr[e^ t _MNaYdgeu gwviJt`h` DIAnpfvidnziutDe] dALlKgmekbHrIas by Kuta Software LLC-3-Answers to Parallel & Perpendicular Slopes & Equations of Lines (ID: 1)1) 32) -323) -14) -145) 956) 07) -528) -19) 1210) -1311) 7512) -513) -114) 215) y = -34x + 216) y = 14x + 417) y = x - 318) y = -419) y = 83x + 520) y = 23x - 421) y = x - 422) y = x + 2]
