Infinite Geometry - Scale Factors - Mathemaddox

1 X d2I0C1t7[ zKRultTaZ fSeoifbt\w_atrGeJ uL^L^C[.g D iAMljld ordisgwh]tXsE yrze\ w gMrakd[eY sw_iotOhd EIBnefQi^n[iytweY WGYeLoQmVelt] by Kuta Software LLCAW 11 FactorsName_____ X v2i0C1g7Z ^Kduxt^ap FSroAfTtgw[aLrvez ] CAglplm GrUiggqhQt^sp Grcehs[emr` polygons in each pair are similar. Find the missing side ) 14?2121242) 14?2112213) 203024?4) ? polygons in each pair are similar. Find the Scale factor of the smaller figure to the ) 38866166) 12283235407) 25203024248) 181591612 R C2h0H1A7a bKvuttkal QSYoVfMtMwrarrBed ` d _ADlilB wrbiHgshXtmsh n qMpa^dbem ]w`ittlhB ]IqnQfNiRneiXtge\ by Kuta Software LLC-2-Solve for x. The polygons in each pair are ) 24x + ) 12x + 1020203511) 2x - 12141430353512) 1616640403x - 613) A Scale model has a length of 10cm. Theoriginal had a length of 80cm. Determinethe Scale ) A Scale model has a length of 8cm.]

2 Theoriginal had a length of 20cm. Determinethe Scale ) A Scale model has a length of 70cm . Theoriginal had a length of 30cm. Determinethe Scale ) A Scale model has a length of 40cm. Theoriginal had a length of 25cm. Determinethe Scale factor. j Z2x0x1s7I lKCuNtiaY WSxoTfLtbwFa\rYeV _ \AZlRlm ^rgiUgKhetnsF k xMhaadCej nwKimtfhk SIOnQfAiBnniztEeR kGJeIoNmyeYt\ by Kuta Software LLC-3-17) A Scale model has a length of 6cm. Theoriginal had a length of 2m. Determine thescale ) A Scale model has a length of 40cm. Theoriginal had a length of 8km. Determinethe Scale Scale factor between two similar figures is given. The surface area and volume of thesmaller figure are given. Find the surface area and volume of the larger ) Scale factor = 1 : 5SA = 15 yd V = 30 yd 20) Scale factor = 2 : 5SA = 8 ft V = 104 ft 21) Scale factor = 2 : 3SA = 52 in V = 168 in 22) Scale factor = 2 : 9SA = 24 cm V = 176 cm Each pair of figures is similar.

3 Use the information given to find the Scale factor of the figureon the left to the figure on the ) SA = 343 cm SA = 252 cm 24) SA = 704 ft SA = 275 ft C Y2B0r1[7G MK_uwtBai ASgogfCtTwqagrsem ] GAPlJl\ gr`i^gzhPt_sM z FMZaRdKea XwDiEtOh] qImnLfOiynYixtDe_ by Kuta Software LLC-4-25) V = 13824 km V = 9261 km 26) V = 3672 ft V = 5831 ft Some information about the surface area and volume of two similar solids has been given. Findthe missing ) Solid #1SA = 99 mi V = 675 mi Solid #2SA = 44 mi V = ?28) Solid #1SA = 1280 yd V = 9216 yd Solid #2SA = ?V = 13122 yd 29) 1. 162. 83. 364. 75. 810. 1111. 1212. 713. ) 15. or 5x10-519. sa=375 v=375020. sa=50 v=162521. sa=117 v=56722. sa=486 v=1603823. v=20028. sa=1620 s s2^0H1k7n KKfu\tXaj LS^orfRtswSajrTeg b YAjlplA MriiggzhStMsh H NMGa\dZeX qwoiktQhI FICnvfTi^neiltYeI by Kuta Software LLC-5-Answers to Scale Factors1) 162) 83) 364) 75) 1 : 26) 4 : 57) 5 : 68) 3 : 49) 810) 1111) 1212) 713) 1:814) 2:515) 7:316) 8:517) 3:10018) 1:20 00019) SA = 375 yd , V = 3750 yd 20) SA = 50 ft , V = 1625 ft 21) SA = 117 in , V = 567 in 22) SA = 486 cm , V = 16038 cm 23) 7 : 624) 8 : 525) 8 : 726) 6 : 727) V = 200 mi 28) SA = 1620 yd 29) 30)