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ベクトルの外積の確認 - izumi-math.jp

A b n 1 411 26 1 2 2, 1,2n 22221293n 12 1221 22, 1,2, ,,,,33 3333 3nn 2 1 1 4 62 6 82 2 1, 4, 1a 2,6, 1b , ,px y z ,ap bp 0,0a pb p p 1p 222402601xyzxyzxyz ,y z x 1,2yx zx 2914x 22,33x 2 1221 2, ,, ,,,,3 3333 3x y z 2 1221 2, ,,,,3 3333 3 ..n a b ,a b a b a bn n ,a b ,a b a b ,a b sina bna b ,a b 123123,,,,,aa a abb b b 0,0,//aba b a b n 1a2a3a1a1b2b3b1b 2 33 23 11 31 22 1,,na ba b a ba b a ba b 2 33 2a ba b 1 22 1a ba b 3 11 3a ba b

a とb に垂直なベクトルのひとつをn とすると 1 4 1 1 2 6 1 2 順番通り並び替えると n 2, 1, 2 ここで n 2 1 2 9 32 2 2 であるから

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Transcription of ベクトルの外積の確認 - izumi-math.jp

1 A b n 1 411 26 1 2 2, 1,2n 22221293n 12 1221 22, 1,2, ,,,,33 3333 3nn 2 1 1 4 62 6 82 2 1, 4, 1a 2,6, 1b , ,px y z ,ap bp 0,0a pb p p 1p 222402601xyzxyzxyz ,y z x 1,2yx zx 2914x 22,33x 2 1221 2, ,, ,,,,3 3333 3x y z 2 1221 2, ,,,,3 3333 3 ..n a b ,a b a b a bn n ,a b ,a b a b ,a b sina bna b ,a b 123123,,,,,aa a abb b b 0,0,//aba b a b n 1a2a3a1a1b2b3b1b 2 33 23 11 31 22 1,,na ba b a ba b a ba b 2 33 2a ba b 1 22 1a ba b 3 11 3a ba b


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