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Limiting Reagent Worksheet - Everett Community College

Limiting Reagent Worksheet W 324 Everett Community College Student Support Services Program 1) Write the balanced equation for the reaction that occurs when iron (II) chloride is mixed with sodium phosphate forming iron (II) phosphate and sodium chloride. 2) If 23 grams of iron (II) chloride reacts with 41 grams of sodium phosphate, what is the Limiting Reagent ? How much sodium chloride can be formed? 3) How much of the excess Reagent remains when this reaction has gone to completion? 4) If grams of sodium chloride are formed in the reaction, what is the percent yield of this reaction? Solutions 1) Write the balanced equation for the reaction that occurs when iron (II) chloride is mixed with sodium phosphate forming iron (II) phosphate and sodium chloride. 3 FeCl2 + 2 Na3PO4 Fe3(PO4)2 + 6 NaCl 2) If 23 grams of iron (II) chloride reacts with 41 grams of sodium phosphate, what is the Limiting Reagent ? How much sodium chloride can be formed?

3 PO 4 x 163.94 g Na 3 PO 4 = 126.75 g FeCl 2 3 mole FeCl 2 1 mole Na 3 PO 4 = 20. g Na 3 PO 4 Since we have 41 g Na 3 PO 4, FeCl 2 is the limiting reagent. 23 g FeCl 2 x 1 mole FeCl 2 x 6 mole NaCl x 58.44 g NaCl = 126.75 g FeCl 2 3 mole FeCl 2 1 mole NaCl = 21 g NaCl 3) How much of the excess reagent remains when this reaction has gone to ...

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Transcription of Limiting Reagent Worksheet - Everett Community College

1 Limiting Reagent Worksheet W 324 Everett Community College Student Support Services Program 1) Write the balanced equation for the reaction that occurs when iron (II) chloride is mixed with sodium phosphate forming iron (II) phosphate and sodium chloride. 2) If 23 grams of iron (II) chloride reacts with 41 grams of sodium phosphate, what is the Limiting Reagent ? How much sodium chloride can be formed? 3) How much of the excess Reagent remains when this reaction has gone to completion? 4) If grams of sodium chloride are formed in the reaction, what is the percent yield of this reaction? Solutions 1) Write the balanced equation for the reaction that occurs when iron (II) chloride is mixed with sodium phosphate forming iron (II) phosphate and sodium chloride. 3 FeCl2 + 2 Na3PO4 Fe3(PO4)2 + 6 NaCl 2) If 23 grams of iron (II) chloride reacts with 41 grams of sodium phosphate, what is the Limiting Reagent ? How much sodium chloride can be formed?

2 23 g FeCl2 x 1 mole FeCl2 x 2 mole Na3PO4 x g Na3PO4 = g FeCl2 3 mole FeCl2 1 mole Na3PO4 = 20. g Na3PO4 Since we have 41 g Na3PO4, FeCl2 is the Limiting Reagent . 23 g FeCl2 x 1 mole FeCl2 x 6 mole NaCl x g NaCl = g FeCl2 3 mole FeCl2 1 mole NaCl = 21 g NaCl 3) How much of the excess Reagent remains when this reaction has gone to completion? 41 g Na3PO4 - 20. g Na3PO4 = 21 g Na3PO4 4) If grams of sodium chloride are formed in the reaction, what is the percent yield of this reaction? g NaCl x 100 = 77% 21 g NaCl


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