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Physics Formulas for Class 11 and Class 12

|pg. 11 VectorsNotation:~a=ax +ay +az kMagnitude:a=|~a|= a2x+a2y+a2zDot product:~a ~b=axbx+ayby+azbz=abcos Cross product:~a~b~a ~b k~a ~b= (aybz azby) + (azbx axbz) + (axby aybx) k|~a ~b|=absin 2 KinematicsAverage and Instantaneous Vel. and Accel.:~vav= ~r/ t,~vinst=d~r/dt~aav= ~v/ t~ainst=d~v/dtMotion in a straight line with constanta:v=u+at, s=ut+12at2, v2 u2= 2asRelative Velocity:~vA/B=~vA ~vBProjectile Motion:xyOusin ucos u RHx=utcos , y=utsin 12gt2y=xtan g2u2cos2 x2T=2usin g, R=u2sin 2 g, H=u2sin2 2g3 Newton s Laws and FrictionLinear momentum:~p=m~vNewton s first law:inertial s second law:~F=d~pdt,~F=m~aNewton s third law:~FAB= ~FBAF rictional force:fstatic, max= sN, fkinetic= kNBanking angle:v2rg= tan ,v2rg= +tan 1 tan Centripetal force:Fc=mv2r, ac=v2rPseudo force.

Physics Formulas for Class 11 and Class 12 Author: Jitender Singh Subject: Physics formulas from Mechanics, Waves and Oscillations, Optics, Heat and Thermodynamics, Electricity and Magnetism and Modern Physics. Also includes the value of Physical Constants. Helps in quick revision for CBSE, NEET, JEE Mains, and JEE Advanced.

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Transcription of Physics Formulas for Class 11 and Class 12

1 |pg. 11 VectorsNotation:~a=ax +ay +az kMagnitude:a=|~a|= a2x+a2y+a2zDot product:~a ~b=axbx+ayby+azbz=abcos Cross product:~a~b~a ~b k~a ~b= (aybz azby) + (azbx axbz) + (axby aybx) k|~a ~b|=absin 2 KinematicsAverage and Instantaneous Vel. and Accel.:~vav= ~r/ t,~vinst=d~r/dt~aav= ~v/ t~ainst=d~v/dtMotion in a straight line with constanta:v=u+at, s=ut+12at2, v2 u2= 2asRelative Velocity:~vA/B=~vA ~vBProjectile Motion:xyOusin ucos u RHx=utcos , y=utsin 12gt2y=xtan g2u2cos2 x2T=2usin g, R=u2sin 2 g, H=u2sin2 2g3 Newton s Laws and FrictionLinear momentum:~p=m~vNewton s first law:inertial s second law:~F=d~pdt,~F=m~aNewton s third law:~FAB= ~FBAF rictional force:fstatic, max= sN, fkinetic= kNBanking angle:v2rg= tan ,v2rg= +tan 1 tan Centripetal force:Fc=mv2r, ac=v2rPseudo force.

2 ~Fpseudo= m~a0, Fcentrifugal= mv2rMinimum speed to complete vertical circle:vmin, bottom= 5gl, vmin, top= glConical pendulum:T= 2 lcos gmgTl 4 Work, Power and EnergyWork:W=~F ~S=FScos , W= ~F d~SKinetic energy:K=12mv2=p22mPotential energy:F= U/ xfor conservative , Uspring=12kx2 Work done by conservative forcesis path indepen-dent and depends only on initial and final points: ~Fconservative d~r= theorem:W= KMechanical energy:E=U+K. Conserved if forces areconservative in W t, Pinst=~F ~v5 Centre of Mass and CollisionCentre of mass:xcm= ximi mi, xcm= xdm dmCM of few useful ,m2separated byr:m1m2 Crm2rm1+m2m1rm1+m22.

3 Triangle (CM Centroid)yc=h3Ch3h3. Semicircular ring:yc=2r C2r r4. Semicircular disc:yc=4r3 C4r3 r5. Hemispherical shell:yc=r2 Crr26. Solid Hemisphere:yc=3r8Cr3r87. Cone: the height of CM from the base ish/4 forthe solid cone andh/3 for the hollow 2020 by Jitender Singh Ver. 2020 1 Get Our |pg. 2 Motion of the CM:M= mi~vcm= mi~viM, ~pcm=M~vcm, ~acm=~FextMImpulse:~J= ~Fdt= ~pCollision:m1m2v1v2 Before collisionAfter collisionm1m2v 1v 2 Momentum conservation:m1v1+m2v2=m1v 1+m2v 2 Elastic Collision:12m1v12+12m2v22=12m1v 12+12m2v 22 Coefficient of restitution:e= (v 1 v 2)v1 v2={1,completely elastic0,completely in-elasticIfv2= 0 andm1 m2thenv 1= 0 andm1 m2thenv 2= collision withm1=m2:v 1=v2andv 2= Rigid Body DynamicsAngular velocity: av= t, =d dt, ~v=~ ~rAngular Accel.}

4 : av= t, =d dt, ~a=~ ~rRotation about an axis with constant : = 0+ t, = t+12 t2, 2 02= 2 Moment of Inertia:I= imiri2, I= r2dmringmr2disk12mr2shell23mr2sphere25mr 2rod112ml2hollowmr2solid12mr2rectanglem( a2+b2)12abTheorem of Parallel Axes:I =Icm+md2cmI dIcTheorem of Perp. Axes:Iz=Ix+IyxyzRadius of Gyration:k= I/mAngular Momentum:~L=~r ~p,~L=I~ Torque:~ =~r ~F, ~ =d~Ldt, =I OxyP~r~F Conservation of~L:~ ext= 0 = ~L= condition: ~F=~0, ~ =~0 Kinetic Energy:Krot=12I 2 Dynamics:~ cm=Icm~ ,~Fext=m~acm, ~pcm=m~vcmK=12mvcm2+12 Icm 2,~L=Icm~ +~rcm m~vcm7 GravitationGravitational force:F=Gm1m2r2m1m2 FFrPotential energy:U= GMmrGravitational acceleration:g=GMR2 Variation of g with depth:ginside g(1 hR)Variation of g with height:goutside g(1 2hR)Effect of non-spherical earth shape ong:gat pole> gat equator( Re Rp 21 km)Effect of earth rotation on apparent weight.

5 Mg =mg m 2 Rcos2 Rm 2 Rcos mg~ Orbital velocity of satellite:vo= GMRE scape velocity:ve= 2 GMRK epler s laws:voaFirst:Elliptical orbit with sun at one of the :Areal velocity is constant. ( d~L/dt= 0).Third:T2 a3. In circular orbitT2=4 Simple Harmonic MotionHooke s law:F= kx(for small elongationx.)Acceleration:a=d2xdt2= kmx= 2xTime period:T=2 = 2 mkDisplacement:x=Asin( t+ )Velocity:v=A cos( t+ ) = A2 x2 Potential energy:U=12kx2 A0 AxUKinetic energyK=12mv2 A0 AxKTotal energy:E=U+K=12m 2A2 Get 2020 by Jitender Singh Ver. 2020 1 Get Our |pg. 3 Simple pendulum:T= 2 lglPhysical Pendulum:T= 2 ImglTorsional PendulumT= 2 IkSprings in series:1keq=1k1+1k2k1k2 Springs in parallel:keq=k1+k2k1k2 Superposition of two SHM s:~A1~A2~A x1=A1sin t, x2=A2sin( t+ )x=x1+x2=Asin( t+ )A= A12+A22+ 2A1A2cos tan =A2sin A1+A2cos 9 Properties of MatterModulus of rigidity:Y=F/A l/l, B= V P V, =FA Compressibility:K=1B= 1 VdVdPPoisson s ratio: =lateral strainlongitudinal strain= D/D l/lElastic energy:U=12stress strain volumeSurface tension:S=F/lSurface energy:U=SAExcess pressure in bubble: pair= 2S/R, psoap= 4S/RCapillary rise.

6 H=2 Scos r gHydrostatic pressure:p= ghBuoyant force:FB= V g= Weight of displaced liquidEquation of continuity:A1v1=A2v2v1v2 Bernoulli s equation:p+12 v2+ gh= constantTorricelli s theorem:vefflux= 2ghViscous force:F= AdvdxStoke s law:F= 6 rvFvPoiseuilli s equation:Volume flowtime= pr48 llrTerminal velocity:vt=2r2( )g9 Visit to buy IIT JEE Physics : Topic-wise Complete Solutions and our other books. Written by IITians, Forewordby Dr. HC Verma, Appreciated by 2020 by Jitender Singh Ver. 2020 1 Get Our Book


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