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Posttest Pharmacy Calculations Part 2 1. of milliliters ...

Posttest Pharmacy Calculations part 2. 1. A boy, 4 years of age, is written a prescription for amoxicillin 75 mg orally 3 times daily. The concentration of the suspension on hand in the Pharmacy is 125 mg per 5 mL. Calculate the number of milliliters that the child should receive with each individual dose. A. 5 mL. B. 7 mL. C. 3 mL**. D. 2 mL. Correct Answer: C. Solution: 125 mg : 5 mL :: 75 mg : X mL (75)(5) :: (125)(X) X = 375 125 = 3 mL. 2. How many milliliters of a stock solution are required to make 2 L of solution? How many mL of solvent will be required to carry out the dilution?

Posttest Pharmacy Calculations Part 2 . 1. A boy, 4 years of age, is written a prescription for amoxicillin 75 mg orally 3 times daily. The concentration of the suspension on hand in the pharmacy is 125 mg per 5 mL.Calculate the number

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Transcription of Posttest Pharmacy Calculations Part 2 1. of milliliters ...

1 Posttest Pharmacy Calculations part 2. 1. A boy, 4 years of age, is written a prescription for amoxicillin 75 mg orally 3 times daily. The concentration of the suspension on hand in the Pharmacy is 125 mg per 5 mL. Calculate the number of milliliters that the child should receive with each individual dose. A. 5 mL. B. 7 mL. C. 3 mL**. D. 2 mL. Correct Answer: C. Solution: 125 mg : 5 mL :: 75 mg : X mL (75)(5) :: (125)(X) X = 375 125 = 3 mL. 2. How many milliliters of a stock solution are required to make 2 L of solution? How many mL of solvent will be required to carry out the dilution?

2 A. 571 mL of stock solution and 1429 mL of solvent**. B. 670 mL of stock solution and 1330 mL of solvent C. 150 mL of stock solution and 1850 mL of solvent D. 450 mL of stock solution and 1550 mL of solvent Correct Answer: A. Solution: Q1 C1 = Q2 C2 Q1( ) = (2000 mL)( ) 400 = ( )(Q1) Q1 = 571 mL. a) 2000 mL 571 mL = 1429 mL of solvent 3. A 45 gm tube of 1% clotrimazole cream is combined with 15 gm of base. What is the new percent strength? A. B. **. C. D. Correct Answer: B. Solution: Q1 C1 = Q2 C2 (45)(1%) = (60)(C2) 45 60 = C2 C2 = 4. A physician writes an order for 1000 mL of dextrose to be infused at 75 mL/hour.

3 This large volume concentration is not available in the Pharmacy , so it must be compounded using 50%. dextrose and 5% dextrose. Using the method of alligation, how many mL of 50% dextrose will be required for the compound? A. 167 mL**. B. 125 mL. C. 133 mL. D. 216 mL. Correct Answer: A. Solution: Alligation 50 % part 5% parts 45 total parts a. 50% dextrose ( 45) 1000 mL = 167 mL of 50% dextrose 5. BM is a woman, 27 years of age, who is 63 inches tall and weighs 167 lbs. Calculate her body surface area (BSA). A. m2. B. m2. C. m2**. D. m2. Correct Answer: C. Solution: BSA = (63 167) 3131 = m2.

4 6. A woman, 7 years of age, has been prescribed a methotrexate (MTX) dose of 25 mg/m2/week. The child is 110 cm tall and weighs 29 kg. Which weekly dose is correct? A. 31 mg B. 15 mg C. 11 mg D. 24 mg**. Correct Answer: D. Solution: BSA = (110 29) 3600 = Dose = 25 mg/m2 m2 = 24 mg 7. CR is a man, 25 years of age, who is 105 kg and is 71 inches tall. Calculate his ideal body weight (IBW). A. 85 kg B. 65 kg C. 71 kg D. 75 kg**. Correct Answer: D. Solution: IBW = 50 kg + ( )(71 60) = 75 kg 8. JB is a woman, 17 years of age, who is 71 kg and 66 in tall. Calculate her IBW. A. 65 kg B. 59 kg**.

5 C. 75 kg D. 48 kg Correct Answer: B. Solution: IBW = kg + ( )(66 60) = 59 kg 9. A common definition of morbid obesity is a weight that is greater than what percentage of IBW? A. 75%. B. 100%. C. 200%**. D. 150%. Correct Answer: C. Solution: The definition or cutoff for obesity varies by institution, although patients who have body fat contents ranging from 25% to 30% of their actual body weight are generally considered obese. A common definition of extreme or morbid obesity is a weight that is greater than 200% of IBW. 10. A physician writes the following order: gentamicin mg/kg/dose every 8 hours.

6 The patient is an obese man, 33 years of age; so gentamicin must be dosed using an adjusted body weight (ABW) with a dose correction factor of The patient is 185 kg and is 69 inches tall. Calculate the amount in milligrams of each individual dose. A. 175 mg**. B. 180 mg C. 135 mg D. 210 mg Correct Answer: A. Solution: IBW = 50 kg + ( )(69 60) = 71 kg ABW = 71 + ( )(185 71) = 117 kg Dose = mg/kg 117 kg = 175 mg


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